KUNAL GAURAV 7 years AGO
Odds in favour of event A occurring = Pr(A)/Pr(A')
Odds against event A occurring =Pr(A')/Pr(A)
Probability of occurring event = Pr(A)/[Pr(A)+Pr(A')]
In the question
Pr(A')/Pr(A)=5/7 (Since we are given odds against the event)
So probability of occurring the event = 7/(5+7) = 7/12
Like? Yes (18) | No (5)Shubhankur Manuja 7 years AGO Odds against event A occurring =Pr(A')/Pr(A)
Probability of occurring event = Pr(A)/[Pr(A)+Pr(A')]
In the question
Pr(A')/Pr(A)=5/7 (Since we are given odds against the event)
So probability of occurring the event = 7/(5+7) = 7/12
Odd against of a event=(Prob. of Losing)/(Prob. of Winning)
if P is Prob of happening (winning) of event then
=> (1-P)/P = 5/7
=> 7-7P = 5P
=> 12P = 7
=> P = 7/12
Like? Yes (11) | No (1)Alok Kumar 7 years AGO if P is Prob of happening (winning) of event then
=> (1-P)/P = 5/7
=> 7-7P = 5P
=> 12P = 7
=> P = 7/12
odd against = 5/7 so probability = 7 /12
7/(5+7)
Like? Yes (7) | No (2)Mariappan 7 years AGO 7/(5+7)
5:7 means 5 chance of against and 7 chance of occurrence.Thus prob of occurring is 7/12
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odds aginst=nonoccurence/ occurence;
P(occurence)=occurence/total
Like? Yes (2) | No Ankit Shukla 7 years AGO P(occurence)=occurence/total
since the probility odds against any event is =5/12
so the probility of its occurence is=1-(5/12)=7/12
Like? Yes (3) | No (1)sanjay singh 7 years AGO so the probility of its occurence is=1-(5/12)=7/12
total probability=1
odds against the event=5/12
probability=1-5/12=7/12
Like? Yes (2) | No sneha 7 years AGO odds against the event=5/12
probability=1-5/12=7/12
against is in the ratio 5:7
so,total sample space is (5+7)=12
against is 5 parts of 12
so probability of occurrence is 7 parts of 12 i.e.,7/12
Like? Yes (2) | No Tanu 7 years AGO so,total sample space is (5+7)=12
against is 5 parts of 12
so probability of occurrence is 7 parts of 12 i.e.,7/12
(1-p)/p =5/7
p=7/12
Like? Yes (2) | No Md Intshamuddin 7 years AGO p=7/12
Odds AGAINST event = P(not E)/P(E) = 5:7
P(not E)/P(E) = 5:7
=> P(E)=7/12
Like? Yes (4) | No (3)rahul jha 7 years AGO P(not E)/P(E) = 5:7
=> P(E)=7/12
Pr(A')/Pr(A) = 5/7
So probability of occurring of the event = 7/(5+7)
=7/12
Like? Yes (3) | No (2)Mayuresh Srivastava 7 years AGO So probability of occurring of the event = 7/(5+7)
=7/12
odds against=prob. of non-occurrence/prob. of occurrence
5/7=(1-p)/p
p=7/12
Like? Yes (1) | No Chandni Maurya 7 years AGO 5/7=(1-p)/p
p=7/12
ans=(5). 7/12
odd against a certain event = m:n =5:7
probability of occurrence=n/(m+n)
=7/(5+7)
=7/12
Like? Yes (3) | No (2)Raju Sharma 7 years AGO odd against a certain event = m:n =5:7
probability of occurrence=n/(m+n)
=7/(5+7)
=7/12
odd against a event occering =p(a')/p(a)
p(a')=1-p(a) and then p(a')/p(a)=5/7
solving this p(a)=5/12;
Like? Yes (2) | No (1)praneeth 7 years AGO p(a')=1-p(a) and then p(a')/p(a)=5/7
solving this p(a)=5/12;
odds against a certain event =p(A')/p(A).we require its occurrence.so,p(A)=7/12.
Like? Yes (1) | No Kushal Saraf 7 years AGO Odds AGAINST event = P(not E)/P(E)
probability of occurence=7/12
Like? Yes (2) | No (1)ALOK KUMAR 7 years AGO probability of occurence=7/12
ODD AGAINST MEANS P(E')/P(E)=5/7 GIVEN
SO P(E)=P(E)/(P(E)+P(E'))=7/12
Like? Yes (1) | No Jagadeesh Rampati 7 years AGO SO P(E)=P(E)/(P(E)+P(E'))=7/12
odd against event i.e (1-p)/p=5/7
from above we get p=7/12
probability of occuring an event=7/12
from above we get p=7/12
probability of occuring an event=7/12
Like? Yes (1) | No bindu 7 years AGO
odds against an event is (1-p):p=5:7.so probability of occurrence is 7/12
Like? Yes (1) | No ShAg 7 years AGO 
Odds AGAINST event = P(not E)/P(E) = 5:7
P(not E)/P(E) = 5:7
=> P(E)=7/12
Like? Yes (4) | No (3)rahul jha 7 years AGO P(not E)/P(E) = 5:7
=> P(E)=7/12
Pr(A')/Pr(A) = 5/7
So probability of occurring of the event = 7/(5+7)
=7/12
Like? Yes (3) | No (2)Mayuresh Srivastava 7 years AGO So probability of occurring of the event = 7/(5+7)
=7/12
odds against=prob. of non-occurrence/prob. of occurrence
5/7=(1-p)/p
p=7/12
Like? Yes (1) | No Chandni Maurya 7 years AGO 5/7=(1-p)/p
p=7/12
ans=(5). 7/12
odd against a certain event = m:n =5:7
probability of occurrence=n/(m+n)
=7/(5+7)
=7/12
Like? Yes (3) | No (2)Raju Sharma 7 years AGO odd against a certain event = m:n =5:7
probability of occurrence=n/(m+n)
=7/(5+7)
=7/12
odd against a event occering =p(a')/p(a)
p(a')=1-p(a) and then p(a')/p(a)=5/7
solving this p(a)=5/12;
Like? Yes (2) | No (1)praneeth 7 years AGO p(a')=1-p(a) and then p(a')/p(a)=5/7
solving this p(a)=5/12;
odds against a certain event =p(A')/p(A).we require its occurrence.so,p(A)=7/12.
Like? Yes (1) | No Kushal Saraf 7 years AGO Odds AGAINST event = P(not E)/P(E)
probability of occurence=7/12
Like? Yes (2) | No (1)ALOK KUMAR 7 years AGO probability of occurence=7/12
ODD AGAINST MEANS P(E')/P(E)=5/7 GIVEN
SO P(E)=P(E)/(P(E)+P(E'))=7/12
Like? Yes (1) | No Jagadeesh Rampati 7 years AGO SO P(E)=P(E)/(P(E)+P(E'))=7/12
odd against event i.e (1-p)/p=5/7
from above we get p=7/12
probability of occuring an event=7/12
Like? Yes (1) | No bindu 7 years AGO from above we get p=7/12
probability of occuring an event=7/12
odds against an event is (1-p):p=5:7.so probability of occurrence is 7/12
Like? Yes (1) | No ShAg 7 years AGO odds against = 5:7
i.e. 7/(5+7) = 7/12
Like? Yes (1) | No Rishav kuamr 7 years AGO i.e. 7/(5+7) = 7/12
odd's against of a certain event is m:n
then probability of not happening a is given by
m/m+n
so probability of a=p(a)=n/m+n
in this question probability of its occurrence is
m=5,n=7
p(a)=7/5+7=7/12
Like? Yes (3) | No (3)komal kirti 7 years AGO then probability of not happening a is given by
m/m+n
so probability of a=p(a)=n/m+n
in this question probability of its occurrence is
m=5,n=7
p(a)=7/5+7=7/12
odds against=5/7; odd against=p(not E)/p(E);
5/7=(5/12)/x; x=probability of occurance=7/12
Like? Yes (1) | No (1)Anil Kumar Bharti 7 years AGO 5/7=(5/12)/x; x=probability of occurance=7/12
7/5 Odds Explained
Exp:
5:7 = 5/7 that means 5/12
Againt odds means : 1-5/12 =7/12 Ans
Like? Yes (1) | No (1)richa ahuja 7 years AGO 5:7 = 5/7 that means 5/12
Againt odds means : 1-5/12 =7/12 Ans
odds against=unfavourable outcomes/favourable outcomes
odds in favour=fav/unfav
here odds against=5/7
therefore odds in favour=7/5
or probability of its occurrence=7/12
Like? Yes (2) | No (2)odds in favour=fav/unfav
here odds against=5/7
therefore odds in favour=7/5
or probability of its occurrence=7/12
Odds 7/5
Harleen Chadha 7 years AGOif odds against an event = m:n
Then the probability of its occurrence = n / (m+n)
Ans: 7/12
Like? Yes (3) | No (4)Manikumar R 7 years AGO Then the probability of its occurrence = n / (m+n)
Ans: 7/12
7/5+7
Like? Yes (2) | No (3)Odds Calculator 7/5
vky 7 years AGO1-(5/(5+7))
Like? Yes (1) | No (2)S.Jenifersmaily 7 years AGO odds against certain event:p(lossing)/p(winning)
p(A')/p(A)=5/7
probability of occurence=7/(5+7)
=7/12
Like? Yes (1) | No (2)p(A')/p(A)=5/7
probability of occurence=7/(5+7)
=7/12
